So for our sequence that I mentioned before, E plus S going to ES going to E plus P we have two reactions going on, one and two, which would each have their own rate equation. Rate one would be equal to rate constant K1 times the two starting material concentrations, which are E and S, while rate two would be equal to K2 times the concentration ... ToExpression[input] gives the expression obtained by interpreting strings or boxes as Wolfram Language input. ToExpression[input, form] uses interpretation rules corresponding to the specified form.

Using the equation C1V1 = C2V2, where C1=10 mM, C2=50 μM, V2=20 ml and V1 is the unknown: Enter 10 into the Concentration (start) box and select the correct unit (millimolar) Enter 50 into the Concentration (final) box and select the correct unit (micromolar)

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The practice of statistics 5th edition pdf chapter 9

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